Find count of repeated letters (sequence)
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Sir,
How to find the no. of repeated sequence (letters) in the given sentence.
for example, a="I want THAAAAAT APPPPPLE ):):): totally unprepared";
The No. of repeated sequences are: 3
ie.,
1. THAAAAAT
2. APPPPPLE
3. ):):):
thanks
4 Comments
Walter Roberson
on 8 Oct 2013
'THAAAAAT' is not a repeated sequence. It contains a repeated sequence.
Could you confirm that the sequences can be more than just adjacent letters such as the A's in THAAAAAT ? The '):' repeating as a unit is intended to be noticed?
Jothi
on 9 Oct 2013
Walter Roberson
on 9 Oct 2013
Your #3, ):):): does not have continuously repeated symbols.
If the repeated sequences are to be identified, then why would all of THAAAAAT be output, and not just AAAAA ?
Jothi
on 9 Oct 2013
Answers (2)
Try to understand the following and fine-tune it to your needs:
n = sum( diff([0, diff(a)==0]) == 1 )
In particular, evaluate
diff(a)==0
and see how your problem actually translates into counting clusters of the outcome of diff(a)==0.
4 Comments
Just to be sure, the repeated sequences are:
AAAAA
PPPPP
ll (in 'totally')
is that right? If so, then my answer works.
Jothi
on 10 Oct 2013
You seem to indicate that one repeated sequence is '):'. As far as I am concerned, there is no simple generic solution if you want to detect repeated, arbitrary patterns. To illustrate,
'AABBCCDDEEFFAABBCCDDEEFF'
Here, repeated patterns are
'AA', 'BB', .., 'FF', 'AABB', 'BBCC', .., 'AABBCC', 'BBCCDD', ..,
'AABBCCDD', 'BBCCDDEE', .., 'AABBCCDDEEFF'
Using regular expressions, we can probably get some solution but it will be prohibitively time consuming.
Sean de Wolski
on 10 Oct 2013
Yeah, every emoticon would have to be predefined. For the chatroom we use here there are even word emoticons like (b) which inserts a frosty beer mug or (ply) which inserts an image of a playing card.
Walter Roberson
on 1 Dec 2016
a='I want THAAAAAT APPPPPLE ):):): totally unprepared';
regexp(a, '(.+)\1{2,}', 'match')
ans =
1×3 cell array
'AAAAA' 'PPPPP' '):):):'
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