random number generation for known sum

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i what do generate some 15 random numbers that sum for each separate value of say, 60 , 70, 40, 65. How would i go abouts this?
sum = [60 70 40 65];
n=15;
b = [ ];
for i = 1:1:n,
a = randi([1,??]);
b = [b a];
end

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 27 Aug 2013
n=60;
m=1:n;
a=m(sort(randperm(60,15)));
b=diff(a);
b(end+1)=60-sum(b)
sum(b)
  13 Comments
Bruno Luong
Bruno Luong on 13 Jul 2020
Edited: Bruno Luong on 13 Jul 2020
The easiest way is perhaps using Roger FEX function, then do some sort of "integering" the float solution
sumatarget = 60
n = 15;
ub = 7;
x = floor([0; cumsum(randfixedsum(n,1,sumatarget,0,ub))]);
x(end) = sumatarget; % prevent floating point error
r = diff(x)
The distribution might be not perfectly uniform but possibly close enough and suitable for what ever you want to do with it.
Tejas
Tejas on 14 Jul 2020
Integering the solution from Roger's function works very well for me. I do not require the numbers to be perfectly uniform. Thanks!

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More Answers (1)

Walter Roberson
Walter Roberson on 27 Aug 2013

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