Info

This question is closed. Reopen it to edit or answer.

how to solve loops conditions ??

1 view (last 30 days)
Samadar Salim
Samadar Salim on 20 Apr 2013
Closed: MATLAB Answer Bot on 20 Aug 2021
any one can help me for this homeworke i couldnt solve
use loops or/and Condition statements to creat this matrix
1 2 3 4 5
6 7 8 9 10
A= 11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
26 27 28 29 30

Answers (2)

Walter Roberson
Walter Roberson on 20 Apr 2013
for K = 1 : 1
A = reshape( 1:30, 5, 6 ) .';
end
  1 Comment
Ahmed A. Selman
Ahmed A. Selman on 21 Apr 2013
Edited: Ahmed A. Selman on 21 Apr 2013
What is for k = 1 : 1 doing here, when it's from 1 to 1 and A is k independent?

Ahmed A. Selman
Ahmed A. Selman on 21 Apr 2013
#1) Using for loops only:
clear
k=0;
for i=1:6
for j=1:5
k=k+1;
A(i,j)=k;
end
end
disp(A)
#2) Using for loop with if statement:
clear
clc
k=0;
j=1;
for i=1:30
k=k+1;
A(j,k)=i;
if fix(i/5)==(i/5)
j=j+1;
k=0;
end
end
disp(A)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!