Potting graphs with if else and for

Here i wanted to plot a graph wit these conditions. but it does not plot a graph. figure remains empty without a graph. how can i fix this

t = -4:0.1:4;
    for k1 =1:length(t)
        if (t(k1)>-4) && (t(k1)<-2)
             x(k1) = (t(k1).^2) - (2.*t(k1))+3;
        elseif (t(k1)>-2) && (t(k1)<2)
             x(k1) = 4*cos(t(k1)*(2*pi*t(k1) - pi./8)) + 3*sin(2*pi*t(k1));
        elseif (t(k1)>2) && (t(k1)<4)
             x(k1) = sin(t(k1))./t(k1);
    end
end
plot (t,x)

Answer 1

[Sindar]

If it throws an error, please include that information.

If that error is what I'm seeing:

Error using plot. Vectors must be the same length.

then the issue is that you're conditions don't include an x-value when t=4 (or -2,2, but these will be filled in with zeros). You can use <=, >=, or you don't want those points plotted, insert NaNs:

t = -4:0.1:4;
for k1 =1:length(t)
    if (t(k1)>-4) && (t(k1)<-2)
        x(k1) = (t(k1).^2) - (2.*t(k1))+3;
    elseif (t(k1)>-2) && (t(k1)<2)
        x(k1) = 4*cos(t(k1)*(2*pi*t(k1) - pi./8)) + 3*sin(2*pi*t(k1));
    elseif (t(k1)>2) && (t(k1)<4)
        x(k1) = sin(t(k1))./t(k1);
    else
        x(k1) = nan;
    end
end
plot(t,x)

[Gayathri Thilakrathne]

Thank you very much!