How to create multiple matrices with different sizes without a loop?
2 views (last 30 days)
Show older comments
Say I have a matrix with M elements. In this case its 3.
A = [1 2 3];
And I want to create M vectors with N random numbers from the interval 0 to each of the element in A.
X = randi([0,A(1)], 1, N)
Y = randi([0,A(2)], 1, N)
Z = randi([0,A(3)], 1, N)
How can I do this without using loops? Is it possible?
0 Comments
Accepted Answer
James Tursa
on 7 Oct 2020
You will either need to use loops, or hide the loops behind a function call (e.g., arrayfun):
result = arrayfun(@(x)randi([0 x],1,N),A,'uni',false);
0 Comments
More Answers (1)
Walter Roberson
on 7 Oct 2020
N = 100;
A = [1 2 3];
M = length(A);
XYZcell = num2cell(floor(rand(M, N) .* (A(:)+1)), 2);
[X, Y, Z] = XYZcell{:};
counts = accumarray(Z(:)+1, 1);
bar(0:3, counts)
1 Comment
Walter Roberson
on 7 Oct 2020
Note: this method is very slightly biased against 0 -- but not enough that you would notice.
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!