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summing elements of an array until a value appears

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I'm trying to execute a for loop that looks at permutations of a set and sums all the elements until a specific element 'k' is reached.
rather than sum(line(1:k)) i need effectively sum(line(1:'k')) but inputting that exactly doesn't work. Any ideas?
if sum(line(1:k))>=q && (sum(line(1:k))-k)<q

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Turlough Hughes
Turlough Hughes on 29 Jan 2020
You wouldn't need a loop, you could just use cumsum and find your value in the output.
Thomas Gvero
Thomas Gvero on 29 Jan 2020
Sorry I wasn't very clear. I am basically trying to sum every permutation of an array up to and including a particular element (not always the same index each time). For example, if I was summing up to 2, and my permutations were:
1,2,3
1,3,2
2,1,3
then my sums would go up to the number 2 not the second element. The sums would be 3,6,2 repectively.
Thomas Gvero
Thomas Gvero on 29 Jan 2020
this is running in a wider for loop of a function so i need it to output exactly what i need each time which is why i need the second loop

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Accepted Answer

Mohammad Sami
Mohammad Sami on 29 Jan 2020
a = [1 1 1 2 3 4 2];
i = find(a==2,1,'first');
if ~isempty(i)
val = sum(a(1:i));
else
val = sum(a);
end

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More Answers (2)

the cyclist
the cyclist on 29 Jan 2020
Here is one way.
% Inputs
inputVector = [5 4 3 2 1];
inputValueToFind = 2;
% Find the location of the index
idxEnd = find(inputVector==inputValueToFind,1);
% Sum up to that index
sum(inputVector(1:idxEnd))

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Turlough Hughes
Turlough Hughes on 29 Jan 2020
Edited: Turlough Hughes on 29 Jan 2020
Say your array is called data:
q=2;
data = [1 2 3; 1 3 2; 2 1 3; 1 0 3; 1 2 2]; % Includes rows without any values = q, and repeated q.
You could then get the cumulative sum of values up to the first occurence of q in each row as follows:
[ ~,k ] = max(data == q,[],2); % Index for first column equal to q in each row.
k(~any(data == q,2)) = 0 % Case for rows that have no values == q.
for c = 1:numel(k)
csums(c,1) = sum( data(c,1:k(c)) );
end
Here, data == q is a logical array of all values in data that are equal to q. Taking the max along each row will return the "first" index for a given row in data being equal to q. The second line accounts for cases where no values are equal to q.

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