the integer part of the division

hello everyone

how do i get the integer part of the output of a division i.e. 23/5=4 (and the remainder is 3)

[Shashank Agarwal]

floor(23/5)

[Walter Roberson]

See my reply for when to use floor() and when not to.

http://www.mathworks.com/matlabcentral/answers/49923-the-integer-part-of-the-division#answer_60983

Answer 1

[Azzi Abdelmalek]

 fix(23/5)   % integer part

 rem(23,5)   % remainder
 %or 
 mod(23,5)

[vaggelis vaggelakis]

thanks mate, i spent much time on looking the help documentation

[Azzi Abdelmalek]

It's fixed with fix

[Royi Avital]

It works only for Float64 and Float32.

For integer types use idivide.

Answer 2

[Walter Roberson]

Consider -23/5 (that is, the case of negative numbers.) Should that be -4 times 5 and remainder -3, or should it be -5 times 5 and remainder 2 ?

If you want the -4 version so that abs() of the "integer part" of -23/5 and 23/5 are the same, then use fix()

If you want the -5 version so that the remainder is always non-negative, then use floor()

You can use either fix() or floor() if you only have positive values, with floor() being preferred (more efficient, mathematically clearer)

Do not use round() even if you have only positive values. round(23/5) is 5, not 4.