regexp for sentence that contains parentheses

I have a *.csv file that I read wih the following command:

filetext = fileread('example_file.csv');

This file contains a header that I would like to read line-by-line. The header contains some lines like:

Experiment name;AFS2_test1
Integration time internal baseline (ms);10.00

To look for the line that matches with the first one ('Experiment name') I do the following:

expr = '[^\n]*Experiment name[^\n]*'
matches = regexp(filetext,expr,'match');
matches =

  1×1 cell array

    {'Experiment name;AFS2_test1'}

But when I search for the second line ('Integration time (ms)') I get:

expr = '[^\n]*Integration time (ms)[^\n]*'
matches = regexp(filetext,expr,'match')

matches =

  0×0 empty cell array

I suspect it has anything to do with the parentheses that enclose the word 'ms' but i'm not sure. Who can help me to define the correct regexp?

[Walter Roberson]

In your pattern use \( and \)

Answer 1

[Guillaume]

Yes, all special regexp characters, [](){}.*+?^$\, have to be escaped with a \, so:

expr = '[^\n]*Integration time \(ms\)[^\n]*'

Answer 2

[Henk-Jan Ramaker]

Thanks a lot for the prompt reply!