Count the same element in a large rows of one column

Hello!

I want to count a specific value of matrix in each row of matrix, the size of the matrix is 421 by 1

Thanks

[Walter Roberson]

Since you only have one column in each row, then the count for each row will be either 0 (the value is not the target) or 1 (the value is the target), so you can just use

YourMatrix == SpecificValue

[Manti Etekia]

Walter Roberson thank you, but from then i want to count all those value and output such as:

value of 9 was 67, Sorry i just start programming

Thank you

Answer 1

[madhan ravi]

uniquevalue = 9; % for example
nnz(matrix==uniquevalue)

Answer 2

[KSSV]

idx = matrix==myvalue ;   % this wlill give logical indices 
T = nnz(idx) ;    % this iwll give you total number of values present 
id = find(idx) ;   % this will give indices/ positions

If you want to know the repeated values. Use unique

[c,ia,ib] = unique(matrix) ;

If you want along woht count the repeated values:

[a,b]=hist(matrix,unique(matrix))

Answer 3

[Andrei Bobrov]

Let A - your vector (421 x 1):

[a,~,c] = unique(A);
out = array2table([a, accumarray(c,1)],'v',{'value','times'});