Error Operands to the || and && operators must be convertible to logical scalar values.

Names = {'RHip','RKnee','RAnkle'};

Why doing this works ok

if~isempty( strfind(Names{1}, 'Hip') || strfind(Names{2}, 'Knee'))

if~isempty( strfind(Names{1}, 'Hip') || strfind(Names{3}, 'Knee'))

but doing this gives the error Operands to the || and && operators must be convertible to logical scalar values.

if~isempty( strfind(Names{3}, 'Hip') || strfind(Names{2}, 'Knee'))

Note in code was missing the ~isempty (i already added it). Nevertheless this dont change the outcome. The problem is that when the first operation give an [ ] the outcome is an error

Answer 1

[Walter Roberson]

strfind can return empty and you cannot use && or || with empty .

strfind finds all occurrences and returns their index . It is not intended to directly answer the question of whether to pattern occurs somewhere Yes or No. With new enough MATLAB use contains()

Answer 2

[Armindo]

KALYAN ACHARJYA

Thanks but that don't solve the problem. The code doesn't work with || neither with |.

[KALYAN ACHARJYA]

Please read the explanation form @Walter sir