Swap the first and last columns

function B = swap_ends(A)
  B = A(:,[end , 2:end-1 , 1]);
end

tried this , but showing error , can any one help ?

Answer 1

[Alessandro Galo]

This works ;)

if size(A,2) ~= 1 & size(A,2) ~= 0
B = A(:,[end , 2:end-1 , 1])
else
    B = A;
end

Answer 2

[madhan ravi]

A=rand(4)         % example matrix   
B = swap_ends(A)  % function call

function B = swap_ends(A)     % function definition
A(:,[1 end])=A(:,[end 1]);
B=A;
end

Gives:

A =

    0.5200    0.8475    0.4965    0.0832
    0.7875    0.0289    0.0663    0.1867
    0.2765    0.5650    0.1179    0.9095
    0.0962    0.7098    0.3063    0.6303


B =

    0.0832    0.8475    0.4965    0.5200
    0.1867    0.0289    0.0663    0.7875
    0.9095    0.5650    0.1179    0.2765
    0.6303    0.7098    0.3063    0.0962
    

A=rand(1,5)         % example row vector/column vector   
B = swap_ends(A)  % function call

function B = swap_ends(A)     % function definition
A([1 end])=A([end 1]);
B=A;
end

Gives:

A =

    0.6604    0.9767    0.4717    0.8576    0.9269

B =

    0.9269    0.9767    0.4717    0.8576    0.6604

[Walter Roberson]

Alessandro Galo's solution does raise the good point that swapping using end subscript will fail if the array is empty on that dimension, so the swap should be protected with isempty()

Answer 3

[Sunil Kumar Giri]

function B = swap_ends(A)
  B = A;
  A(:,1) = A(:,end);
  A(:,end) = B(:,1);
  B = A
end

Answer 4

[ARVIND KUMAR SINGH]

function B = swap_ends(A)
[~,col] = size(A);
if col<2
    B = A;
else
a = A(:,1);
b = A(:,col);
c = A(:,2:col-1);
B =[b c a];
end
end