Solving system of second order differential equations
1 view (last 30 days)
Show older comments
karthik madhamshetty
on 30 Mar 2018
Commented: Torsten
on 4 Apr 2018
Hi,
I tried to solve a system of coupled differential equations.
Can anyone help me with this error?
"Error using odearguments (line 93) ODE_FUNCTION must return a column vector.
Error in ode23tb (line 135) odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in ODE_Function_Solver (line 4) [t,y] = ode45(@ODE_Function,tspan,y0);"
Thank you.
tspan = 0:0.001:2;
y0 = [0 0;0 0;0 0;0 0;0 0;0 0];
[t,y] = ode23tb(@ODE_Function,tspan,y0);
function dydt = ODE_Function(t,y)
m1 = 1;
k1 = 100;
m2 = 1;
k2 = 100;
w = 2*pi*50;
F = sin(w*t);
h = 0.1;
w = 0.1;
% First ODE
dydt(1) = y(2);
dydt(2) = F - k1/m1*(y(1)-y(5))-2*k2/m1*cos(atan((2*h-2*y(3))/w))*(y(1)-y(3));
% SecondODE
dydt(3) = y(4);
dydt(4) = -2*k2/m2*cos(atan((2*h-2*y(3))/w))*(y(3)-y(1));
% Third ODE
dydt(5) = y(6);
dydt(6) = -k1/m1*(2*y(5)-y(1)-y(9))-2*k2/m1*cos(atan((2*h-2*y(7))/w))*(y(1)-y(3));
% Fourth ODE
dydt(7) = y(8);
dydt(8) = -2*k2/m2*cos(atan((2*h-2*y(7))/w))*(y(7)-y(5));
% Fifth ODE
dydt(9) = y(10);
dydt(10) = -k1/m1*(y(9)-y(5))-2*k2/m1*cos(atan((2*h-2*y(11))/w))*(y(1)-y(3));
% Sixth ODE
dydt(11) = y(12);
dydt(12) = -2*k2/m2*cos(atan((2*h-2*y(11))/w))*(y(11)-y(9));
0 Comments
Accepted Answer
lokender Rawat
on 4 Apr 2018
The return type of the parameter from the function block must be a column vector. So, you can add the below statement at the end, inside the function block:
dydt=dydt';
I think you were missing this.
1 Comment
More Answers (0)
See Also
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!