A value belongs to an interval

Hi. Please I need a help with the following,

if 4<A && A<5 

   display(' No value')

   else

    display(' There is a value')

end

if statement does not give the right values of A. Please any one can help me why it does not work properly?

[John D'Errico]

If you have a vector in A, this is the wrong thing to do. An if statement does not apply to each element of a vector, independently.

[Mohamed Saleh]

Yes A is a vector. Please, how can I introduce "if" then?

Answer 1

[Roger Stafford]

To display the values you want write:

A(4<A&A<5)

[Mohamed Saleh]

Thank you very much for your response.

Answer 2

[Akira Agata]

I think what you want to do would be like this. BTW, display function is not recommended. Please use disp function instead.

% Sample data
A = 5*rand(10,1);

idx = (4 < A) & (A < 5);
for kk = 1:numel(idx)
  if idx(kk)
      disp('No value')
  else
      disp('There is a value')
  end
end

[Mohamed Saleh]

Thanks a lot for your answer.