Index exceed matrix dimensions

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Esraa Abdelhalim
Esraa Abdelhalim on 28 Nov 2017
Commented: Walter Roberson on 30 Nov 2017
I am writing this function and for loc = 5 it works fine for any number of popsizes but when I extend it to larger sizes it gives error "Index exceeds matrix dimension" kindly find the code below I tried to test it for popsize = 10 and I found that the f1 and f2 exceeds the 10 counts i dont know why and ofcourse f(i) only contains 10 values hence i get this error I hope I can find help;
function [ f ] = VRPObj8Old1 ( x, popsize, loc, d, a)
f = zeros(popsize,1);
for i = 1: popsize
f1 = 0;
for l = 1:loc
f1 = f1 + x( 1, l, i) * a;
end
f2 = 0;
for j = 1:loc
for o = 1:loc
f2 = f2 + x( j, o, i) * d(j , o);
end
end
f(i) = f1 + f2;
end

Answers (1)

Roger Stafford
Roger Stafford on 28 Nov 2017
You will get that error message if either 'd' is not at least of size loc-by-loc, or 'x' is not at least of size loc-by-loc-by-popsize.
  2 Comments
Esraa Abdelhalim
Esraa Abdelhalim on 29 Nov 2017
Actually I tested this on a 5by5 (loc=5) matrix and it worked fine but when I increase it to larger size it gives me that error ..
Walter Roberson
Walter Roberson on 30 Nov 2017
At the time of failure, what is size(x), size(d), size(a), and what are popsize and loc ?

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