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Hey, I have following function
x = linspace(-0.5,0.5);
y = linspace(-0.5,0.5);
[X,Y] = meshgrid(x,y);
V = 4*(((exp(-20*(((X-0.25)^2) + (Y-0.25)^2)))) + exp(-20*(((X-0.25)^2 + (Y-0.75)^2))) + exp(-20*(((X-0.75)^2 + (Y-0.5)^2))));
figure
contour(X,Y,V,'ShowText','on')
I want to display the function text so I can debug, because Matlab only outputs arrays with zeros. So something is wrong with how I typed in the function.
i.e

Is this possible in MATLAB 2016b?
Thank you
5 Comments
Adam
on 23 Sep 2016
Simplest option would probably be to split it across a number of lines with intermediate variables. Maths all on one line with so many brackets may look neat and space-saving, but it can be more trouble than it is worth when it doesn't work correctly.
Stephen23
on 23 Sep 2016
@Hakan Ole Ensrud Abediy: Splitting this onto several intermediate calcaultions, exactly as Adam has suggested, will be the simplest answer. Then you can check (by hand) that each intermediate step is correct.
Rena Berman
on 14 Sep 2017
(Answers Dev) Restored edit
Rena Berman
on 26 Dec 2017
(Answers Dev) Restored edit
Answers (2)
Walter Roberson
on 24 Sep 2016
0 votes
Your bug is that you used the ^ operator instead of the .^ operator. For a square matrix Z, Z^2 is Z*Z, the matrix algebraically multiplied by itself, whereas you want Z.*Z, which is each element multiplied by itself.
shegaw mamo
on 16 Aug 2019
0 votes
function dx = cancerhealthcells(~, x)
dx = [2; 1];
L=15;
ommega=50
alpha1 = 0.1;
alpha2 = 0.45;
kappa1 = 0.65;
kappa2 = 1;
beta1 = 0.11;
beta2 = 0.15;
epsilon = 0.05;
gamma = 0.35;
dx(1) = alpha1*x(1)-alpha1*x(1).^2./kappa1-beta1*x(1)*x(2)-epsilon*gamma*x(1);
dx(2) = alpha2*x(2)-alpha2*x(2).^2./kappa2-beta2*x(1)*x(2)-gamma*x(2);
Question: Ommega and L are not in the system of equation. How we can develop matlab syntax including ommega and L using ode45?
1 Comment
Walter Roberson
on 16 Aug 2019
What leads you to expect that they should be present?
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