# Similar to wind rose

6 views (last 30 days)
Fredrik on 13 Dec 2011
Hi. I am looking for something like a wind rose, but with scatter points instead. I have vector Direction=[15,78,66,39,254,345]; and also vector Measurement=[1.1,1.2,0.9,2.0,0.8,1.6]; Now I would like to have each value, not as a histogram, but as a scatter point in the circular plot. The farther the point is away from origin, the larger the value should be. The angle from y-axis should be the same as the value in Direction, oriented to the right. So 90 is in east direction.
All suggestions and ideas are very much appreciated!
/Fredrik

#### 1 Comment

Fredrik on 13 Dec 2011
I want polar() but with 0 pointing up, and 90 degrees should be to the right, 180 down, and 270 degrees to the left, and everything in degrees.

Fredrik on 13 Dec 2011
Best answer for all future noobies like me to solve this is : add view(90,-90) on the row after your plot, and everything looks perfect! Dont bother about altering your input data, it is not neccessary, atleast not for me.

#### 1 Comment

Fredrik on 16 Dec 2011
Okey,I was wrong. Angles input to the program should be .*(pi/180); in the code.

Walter Roberson on 13 Dec 2011
To achieve the rotation, feed in ((90 - direction) * pi/180) as the theta, and change the text labels on the axis (which you needed to do anyhow because you wanted degrees.)

Fredrik on 13 Dec 2011
Will that -90 be enough? That will only turn it counter clockwise, with 270 still to the right...
Fredrik on 13 Dec 2011
And also, when i use:
polar(Direction.*(2*pi-(2*pi/360)),Measurement,'c.')
I actually get the axis in degrees to start with. Just that 0 points to the right instead of up, and east and west needs to be shifted.

Fredrik on 13 Dec 2011
Is there a way with using view?

#### 1 Comment

Fredrik on 13 Dec 2011
If I take az -91 and el -76 then I am only one half rotation from having everything perfect..