How to pick a value according to its probability

Hi,
Let's say
P = [0.1 0.3 0.4 0.2]
X = [1 2 5 9]
where P(n) is the probability to select the X(n) element. I wish to make a function that select a "random" element of X according to its probability, like
f = myfun(P,X)
>> f = 2 (occurs around 30%)
thx a lot

4 Comments

what if we have two numbers? Lets say 50% probability to get a=0.05 and b= -0.05
Sorry I am a very beginner in MATLAB
thanks in advance
Nikolas
how to select an element with least probablility

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 Accepted Answer

f = X(find(rand<cumsum(P),1,'first'))

1 Comment

The answers in the other thread took care in case cumsum(P) < 1 as can happen due to round-off error.

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More Answers (3)

The accepted answer is not doing any sanity check, and is sensitive to rounding errors. You should use randsample instead.
To sample n points from X, with replacement, and probabilities P:
randsample( X, n, true, P )
This can also be used with a custom RandStream (see documentation). Be aware that this function does NOT check for negative values in P; check manually if needed.

4 Comments

That was what I was looking for. Thank you !
how to select an element with least probablility
searched a lot for this kind of function

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You can use discretize (which didn't exist when this question was asked originally) to do this. Generate uniform random numbers, bin them using bins whose widths are given by P, and for each bin return the corresponding element of X.
P = [0.1 0.3 0.4 0.2];
X = [1 2 5 9];
values = discretize(rand(1, 1e4), cumsum([0 P]), X);
histogram(values, 'Normalization', 'probability')
The probabilities shown in the histogram should agree pretty closely with the values in P.
The fastest one (100ns-200ns):
function [idx] = get_random_choice(p)
% Random choice with probability
% Example: get_random_choice([0.2,0.7,0.1])
N=length(p); idx=1; cump=0;
r=rand;
while(idx<N)
cump=cump+p(idx);
if(cump>r),break,else,idx=idx+1;end
end
end

Asked:

on 7 Dec 2011

Commented:

on 28 Apr 2023

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