Linear indices from colon operator

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Radek
Radek on 14 Nov 2024 at 15:47
Edited: Stephen23 on 15 Nov 2024 at 8:45
Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

Accepted Answer

Matt J
Matt J on 14 Nov 2024 at 20:18
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

More Answers (2)

Steven Lord
Steven Lord on 14 Nov 2024 at 15:54
See sub2ind.
  2 Comments
Stephen23
Stephen23 on 14 Nov 2024 at 16:10
Edited: Stephen23 on 15 Nov 2024 at 8:45
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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Walter Roberson
Walter Roberson on 14 Nov 2024 at 20:30
sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

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Catalytic
Catalytic on 14 Nov 2024 at 20:22
Edited: Catalytic on 14 Nov 2024 at 20:26
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices
  1 Comment
Matt J
Matt J on 14 Nov 2024 at 20:33
I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

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