Linear indices from colon operator
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Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?
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Accepted Answer
Matt J
on 14 Nov 2024 at 20:18
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);
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More Answers (2)
Steven Lord
on 14 Nov 2024 at 15:54
2 Comments
Stephen23
on 14 Nov 2024 at 16:10
Edited: Stephen23
on 15 Nov 2024 at 8:45
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
array(p1:p2,p3:p4)
Walter Roberson
on 14 Nov 2024 at 20:30
sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Catalytic
on 14 Nov 2024 at 20:22
Edited: Catalytic
on 14 Nov 2024 at 20:26
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices
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Matt J
on 14 Nov 2024 at 20:33
I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.
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