how to use an integral function inside a for loop? i need to find the value of function that chages as i chages .then using this values i need to find another integral.

r0 =0.1

u =[1:7]'

Q =zeros(length(u),1)

E =zeros(length(Q),1)

for i =1:length(u)

Q(i,1) =0.023*(r0^(-1/4))*((u(i))^(-14/4))

f =@(Q) (Q(i)).^(0.3)

E(i,1) =integral(f,1,7)

end

[Steven Lord]

What is the mathematical form of the function you're trying to integrate? Don't show us code, show us an equation. It's not clear from the code you've posted what variable you're trying to integrate over.

[Aparna Sekhar]

Hi Thank you for your respone.Im new to matlab so there may be many mistakes

Q(u)=0.023*r0^(-1/4)*u^(-14/4)

E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du

where u is a range of numbers

u1 is between u0 and u2

[Torsten]

E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du

You define E as a function of u1, but u1 does not appear on the right-hand side.

Answer 1

[Alan Stevens]

Are you looking for something like this?

r0 =0.1;
u =[1:7]';
Q =zeros(length(u),1);
E =zeros(length(Q),1);
Q = @(x)0.023*(r0^(-1/4))*(x.^(-14/4));
f = @(x) Q(x).^0.3;
for i =1:length(u)
    
   u0 = 1; u2 = u(i);
    E(i,1) =integral(f,u0,u2);
    
end
disp(E)

         0
    0.2611
    0.4097
    0.5133
    0.5927
    0.6569
    0.7107

[Aparna Sekhar]

Thank you ..