i want matrix E == matrix B(i want correct answer)

I have tried to run this code many times , even changed the equation , values but i am not able to get the correct answer , here A given is before its transpose of glcm

% Convert to grayscale if necessary
%if size(img, 3) > 1
%img = rgb2gray(img);
%end
I = [0 0 1 1;
    0 0 1 1;
    0 2 2 2;
    2 2 3 3];
A = [2 2 1 0;
    0 2 0 0;
    0 0 3 1;
    0 0 0 1];
D = A';
E = A + D;
E
%glcms = graycomatrix(I);
%glcms
m = 5;
%n = 4;
count = 0;
%count1 = 0;
n = 3;
o = 4;
for i = 1 : 4 
    for j = 1:4 
        for l = 1 : 4 
            for  k = 1 : 4
                x = I(i,1);
                y = I(i,3-1);
                a = I(i,3+1-1);
                b = I(i,2+2-1);
                
                
                if (I(i,j) &&   I(i,n-j)) == (I(i,n-k) && I(i, n+1-k))
                    
                    
                    %disp('Entered the control');
                    
                    % count = count+ 1;
                    %end
                    
                    
                end
                
            end
            B(i,j) = count;
            
            
            
            
        end
        %B(i,j) =  count;
        
        
        %end
        %end
    end
    %if (E == B)
    %  disp('Correct Answer');
    %else
    % disp('Not Correct Answer');
    %end

[Walter Roberson]

                a = I(i,3+1-1);
                b = I(i,2+2-1);

Those always evaluate to the same location, a = I(i, 3) and b = I(i, 3)

Answer 1

[Josh]

E==B is going to do an element-wise comparison, returning a matrix the same size as E and B with logicals (0's, 1's) where the elements in the same positions are equal, sounds like you want a simple true/false if E and B are the same

if you're wanting to build a condition on the entire matrices being equivalent, then you probably want to use:

if isequal(E,B)

...

end

isequal() will output a single true/false value

you could also use all(all(E==B)) to reduce the element-wise comparison to a single true/false

[N. Adithi Rao]

I am sorry but can you give me the exact logical equation which satisfies the condition matrix E == matrix B , i want code : %glcms = graycomatrix(I);

%glcms
m = 5;
%n = 4;
count = 0;
%count1 = 0;
n = 3;
o = 4;
for i = 1 : 4 
    for j = 1:4 
        for l = 1 : 4 
            for  k = 1 : 4
                x = I(i,1);
                y = I(i,3-1);
                a = I(i,3+1-1);
                b = I(i,2+2-1);
                if (I(i,j) &&   I(i,n-j)) == (I(i,n-k) && I(i, n+1-k))

i have tried my level best , whatever conditions and equations i know , with the values i have tried , i only got index is out of bounds or matrix E is not equal to matrix B. so , please anyone i sincerely request you to show me the result

[Josh]

i got index out of bound issues with this line:

if (I(i,j) && I(i,n-j)) == (I(i,n-k) && I(i, n+1-k))

...not quite sure what you're trying to do here but seems kinda confusing with all the logicals (&&,==)

if you want to test for matrix E and B being equivalent: isequal(E,B) returns 1 if equal 0 if not

[Josh]

A=magic(3)

A = 3x3

8 1 6 3 5 7 4 9 2

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

B=randi(9,3)

B = 3x3

7 1 9 6 4 7 8 1 8

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

A==B

ans = 3x3 logical array
   0   1   0
   0   0   1
   0   0   0

A=magic(3);
B=magic(5);
isequal(A,B)

ans = logical
   0

A==B

Arrays have incompatible sizes for this operation.

isequal() can handle matrices of different sizes whereas == cannot

[Josh]

maybe we're miscommunicating and you're really wanting help with the process to generate matrix B such that it will be equal to E?

[N. Adithi Rao]

no you're right.

% Define the original matrix I
I = [0 0 1 1;
     0 0 1 1;
     0 2 2 2;
     2 2 3 3];

% Define matrices A and I
A = [2 2 1 0;
     0 2 0 0;
     0 0 3 1;
     0 0 0 1];

% Calculate matrix D
D = A';

% Calculate matrix E
E = A + D;
E

% Initialize matrix B
B = zeros(size(I));

% Loop through each element of I
for i = 1:size(I, 1)
    for j = 1:size(I, 2)
        % Modify B based on conditions
        % Replace with specific values according to the desired pattern
        % Here we're setting B(i,j) to a value based on the corresponding element in E
        B(i,j) = E(i,j); 
    end
end

B

% Check if matrices E and B are equal
if isequal(E, B)
    disp('Matrices E and B are equal.');
else
    disp('Matrices E and B are not equal.');
end

%Matrices E and B are equal.

[N. Adithi Rao]

Thank you so much

[Josh]

you're very welcome...the latest version is much easier to follow too, nice structure and commeting as well, bravo!