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What's the point of 'isinf' function ?

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In MATLAB we can use '==' operator to check whether the given variable is a finite or infinite. I'm wondering is there any advantages of using 'isinf' function ? like improvement in execution time or handling of some execptions. Any information is helpful. Thank you.

Accepted Answer

Infinite_king
Infinite_king on 8 Jan 2024
Reason 1:-
As @Paul and @Walter Roberson pointed out, 'isinf' will make it easier to check for inf values when complex numbers are involved.
Note :- I will add more reasons if I come across any in the future.

More Answers (1)

Matt J
Matt J on 5 Jan 2024
Edited: Matt J on 5 Jan 2024
For one thing, it covers cases were the inf elements have mixed signs, thus avoiding the overhead of additional operations like abs().
isinf([-inf, 2, inf, 5])
ans = 1×4 logical array
1 0 1 0
  5 Comments
Paul
Paul on 5 Jan 2024
As documented: isinf
"If A contains complex numbers, isinf(A) contains 1 for elements with infinite real or imaginary part, and 0 for elements where both real and imaginary parts are finite or NaN."
Infinite_king
Infinite_king on 8 Jan 2024
Thanks for the comments @Paul and @Walter Roberson. I guess that is a good enough reason to use 'isinf' instead of '==' operator.

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