it says Error in result(i)=​piecewise_​function(x​(i)); result(i)=piecew

% Plotting piecewise function using if else statements.
 
clc; clear all; close all;
 
% assign elements to x
x= -5:0.01:5;
 
 
%iterate over the elements in x one-by-one and calculate the value of f(x)
for i=1:length(x)
    result(i)=piecewise_function(x(i));
end
 
% plot the values of y and x
plot(x,result)
 
xlabel('t-axis')
ylabel('x(t)-axis')
 
title('Piecewise Function f(x)')
grid on
hold off
 
% create a function to plot piecewise function
function result= piecewise_function(x)
    if x >= 2 && x <=5
        result = 3;
   
    end
end

[Frishta]

im doing the function x(t)=3[u(t-2)-u(t-5)]

[Torsten]

How is u(t) defined ?

[Frishta]

3 when 2<=t<=5

Answer 1

[Paul]

What should result be if x < 2 or if x > 5?

[Frishta]

3

[Paul]

No, you want the result to be 3 then 2 < = x <= 5. But what should result be when x is not between 2 and 5?

Maybe consider using the else clause of the if, elseif, else statement.

Regardless, this approach isn't really the best way to solve the problem because it requires you, as the programmer, to basically figure out the answer before writing the code. Instead why not write a single function that takes as input t and returns the corresponding value of u(t) (or x and u(x) if you prefer x instead of t. So that function would look something like

function u = computeu(t)
% comput the value of u here based on the value of t
end

Then you can use this like

y = computeu(t-2) - computeu(t-5);