How does the following loop turn out to be different from the expected 25?

s=0;
I=5;
for i=1:I
    for j=1:i
        s=s+1
    end
end

s = 1

s = 2

s = 3

s = 4

s = 5

s = 6

s = 7

s = 8

s = 9

s = 10

s = 11

s = 12

s = 13

s = 14

s = 15

value(s)

Unrecognized function or variable 'value'.

Answer 1

[Walter Roberson]

Your inner loop is j=1:i . The first time that is j=1:1 . The second time it is j=1:2 . The third time it is j=1:3, then 1:4, then 1:5 . So the inner loop is going to run 1+2+3+4+5 = 15 times.