Rotate an image 180 degrees without library functions

I am tasked with rotating an image using a single line of Matlab code. I'm unsure how to do this without using built-in rotate functions. Any help or advice would be appreciated, thank you!

The function I am supposed to write has one input, that being the image, and expects a "results" output that stores the rotated image.

function result = image_rotation(image)

% insert one line of code here

end

[Walter Roberson]

Please read http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

Hint: the J'th row and K'th column of input should become the J'th-last row and K'th-last column

Answer 1

[Image Analyst]

Hints: Look at the transpose operator -- the apostrophe. Also look at indexing with a negative 1 step.

[rows, columns, numColorChannels] = size(yourImage);
indexes = rows : -1 : 1;

Do not call your variable "image" since that is the name of an important built-in function.

Good luck with your homework.

Answer 2

[James Tursa]

Hint: Take a small example, rotate it 180 degrees, and see where the elements end up. Then consider how you might get that result with indexing into the original matrix.