How i implement Adams Predictor-Corrector Method from general code ?
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Hazel Can
on 25 May 2022
Edited: Lateef Adewale Kareem
on 30 May 2022
Below is the Adams predictor-corrector formula and general code. How can I adapt this code to the above question? Can you please help?
%------------------------------------------------------
% 2-step Predictor-Corrector
% [T,Y]=dd2(f,definition,y,h); definition=[t1,tfinal]
%------------------------------------------------------
function [T,Y]=dd2(f,definition,Y1,h)
t1=definition(1);tfinal=definition(2);T=t1;Y=Y1;
t2=t1+h;
definition=[t1,t2];
[T,Y]=rk2(f,definition,Y1,h) ;
Y2=Y(2);
while t2 <tfinal
t3=t2+h;
P=Y2+h*(3/2*f(t2,Y2)-1/2*f(t1,Y1));
Y3=Y2+h/12*(5* f(t3,P)+8*f(t2,Y2)-f(t1,Y1));
Y1=Y2; Y2=Y3;t1=t2;t2=t3;
T=[T;t3];Y=[Y;Y3];
end
%
%----------------------------------------------
2 Comments
Torsten
on 27 May 2022
You know the correct result of your differential equation.
If you plot Y against T in the calling program and compare the plot with the analytical solution, both should be approximately the same.
If yes, your code is (most probably) correct, if not, it's not.
Accepted Answer
Lateef Adewale Kareem
on 29 May 2022
Edited: Lateef Adewale Kareem
on 30 May 2022
clc; clear all;
h = 0.01;
mu = 20;
f_m = @(t,y) mu*(y-cos(t))-sin(t);
exact = @(t) exp(mu*t)+cos(t);
[t,y_m] = dd2(f_m,[0, 1],exact(0), exact(h), h);
plot(t, exact(t)); hold
plot(t,y_m);
%plot(t,y,'-o');
legend('Exact Solution','Adams predictor-corrector formula')
xlabel('t')
ylabel('y')
title('When h = 0.01 and µ=20')
%------------------------------------------------------
% 2-step Predictor-Corrector
% [T,Y]=dd2(f,definition,y,h); definition=[t1,tfinal]
%------------------------------------------------------
function [T,Y] = dd2(f, definition, Y1, Y2, h)
t1 = definition(1); tfinal = definition(2); t = t1:h:tfinal;
T = t(1:2)'; Y = [Y1;Y2];
for i = 2:numel(t)-1
P = Y(i) + h/2*(3*f(t(i),Y(i))-f(t(i-1),Y(i-1)));
Y(i+1) = Y(i) + h/12*(5*f(t(i+1), P) + 8*f(t(i),Y(i)) - f(t(i-1),Y(i-1)));
T=[T;t(i+1)];
end
end
%
4 Comments
Torsten
on 30 May 2022
As far as I read in your assignment, you should use the exact solution for y1. So neither rk2 nor rk4 is needed.
Lateef Adewale Kareem
on 30 May 2022
Edited: Lateef Adewale Kareem
on 30 May 2022
yeah. he should have sent it in. I have modified the solution to use the exact solution at h
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