How to interchange entries of a n array?

X = [ 4 2 3 6 5 1 ];

x1 = [2 3 1 2];

The following code integange entries of X based on x1

Xnew = X ;

for ii = 1:numel(x1 )

Xnew([ii x1(ii)]) = Xnew([x1(ii) ii ]);

end

Xnew

1- Is there any other faster way to do that?

Answer 1

[Walter Roberson]

1- Is there any other faster way to do that?

There are potentially overlaps: a row might get moved in and moved out again. Therefore the changes must be applied in sequence. The only real improvement would be to calculate the full interchange table first, and then shuffle the rows only once.

Mathematically it could be modeled by a series of permutation matrices, like

[1 0 0 0
 0 0 1 0
 0 1 0 0
 0 0 0 1]

that all got multiplied together to build the final matrix. If you had a number of different X matrices all to be reordered according to the same pattern it just might be worth building that kind of permutation matrix, but it isn't worth it for one X.