Input struct in function
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When I try to run a function that needs constants defined in a struct outside of it, it give the error "Not enough input arguments.". How can I give as input in the function the data struct?
data.fluid.rho = 890;
data.accumulator.V_N2 = 10e-3;
data.accumulator.P_N2 = 2.5e6;
data.accumulator.p0 = 21e6;
data.accumulator.gamma = 1.2;
data.delivery.D23 = 1;
function dydt = problem(t,y,data)
A23 = (data.delivery.D23^2/4)*pi;
end
This is just an example with some line of codes, I get an error on A23, not enough input arguments. I suspect the function doesnt know what data.delivery.D23 is even if its written outside, how can I pass the data structure in the function?
3 Comments
Matt J
on 31 Oct 2021
The error is not caused by anything in the code you've shown us. It is caused by the code where problem() is actually invoked.
Answers (1)
Sulaymon Eshkabilov
on 31 Oct 2021
data.fluid.rho = 890;
data.accumulator.V_N2 = 10e-3;
data.accumulator.P_N2 = 2.5e6;
data.accumulator.p0 = 21e6;
data.accumulator.gamma = 1.2;
data.delivery.D23 = 1;
% A few things are missing:
t = ... % initialize t
y = ... % initialize y
function dydt = problem(t,y,data)
A23 = (data.delivery.D23^2/4)*pi;
dydt = ... % Define dydt
end
2 Comments
Walter Roberson
on 1 Nov 2021
options = odeset('RelTol',1e-9,'AbsTol',1e-9,'Events',@event);
[tt,yy] = ode15s(@(t,y)problem(t,y,data),[t0,tf],[0,0,1e-3,data.accumulator.Vf],options);
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