can not figure this out?

need to find a script that

accepts any number (determined by the program user at run-time) of user-input 2-D force vectors (in component form, with x-, y- magnitudes AND force application point);

• You might ask the user how many vectors will be input (which is easier to code), or
• You can use a signaling mechanism - for example, ask the user whether there are more vectors to input, and continue if there is an affirmative response (which is more interesting and/or user-friendly).

this is what i have but i do not think this in right:

[DGM]

Post formatted code instead of a picture of code. I can't edit or run a picture of code.

I don't see any obvious errors, but you still have to implement a means of setting the maximum number of vectors collected. Some things might be rearranged to make that easier, but I'm not going to transcribe a picture.

[Walter Roberson]

I suggest you use break instead of setting f to 4.

[michail popovits]

%Get a 1 X 3 vector and print the same
A = [1 3];            % to compare the size of vector entered by user is 1 X 3
B = [3 1];            % to compare the size of vector entered by user is 3 X 1
f = 0;                %setting flag to use in loop

% loop untill our requirement(untill 3 try or when entring correct input)

while f<3 
    V = input('Enter a 1 X 3 vector: ');                        %getting user input and adding it two V
    s = size(V);                                                %determining size of entered vector 
    
    if (isequal(s,A)==1)                                        % checking that size of V is 1 X 5
        fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
        disp(V);                                                % displaying V
        f=4;                                                    % setting termination condition for loop
    elseif (isequal(s,B)==1)                                    % checking that size of V is 5 X 1
        fprintf('Error: You entered a 3 X 1 vector! \n');       % errror message displaying
        V = V.';                                                % transposing vector to 1 X 5
        fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
        disp(V);                                                %displaying V
        f=4;                                                    % setting termination condition for loop
    else
        fprintf('Entrored dimesion is wrong!\n');               % printing error when user entry size is wrong
        f = f + 1;                                              %incrementing chance count
    end
end
if(f==3)
    fprintf('Your Chances are over!\n');                        % printing the error message if try is over 
end

[Walter Roberson]

t1 = isequal(3,5)

t1 = logical
   0

class(t1)

ans = 'logical'

t2 = isequal(3,5) == 1

t2 = logical
   0

class(t2)

ans = 'logical'

t3 = isequal(5,5)

t3 = logical
   1

class(t3)

ans = 'logical'

t4 = isequal(5,5) == 1

t4 = logical
   1

class(t4)

ans = 'logical'

Under what circumstances are you expecting isequal(s,A) to have a different class() or size() or value than isequal(s,A)==1 ?

Answer 1

[Kshitij Chhabra]

Hi,

From my understanding you need to take variable amount of 1x3 array inputs from the user and are trying to store them. I've taken the liberty to assume that if the user enters 3 incorrect inputs, the program is terminated.

First Approach:

n=input("Enter Number of Values to be inputted: ");
Value=[];

%Get a 1 X 3 vector and print the same
A = [1 3];            % to compare the size of vector entered by user is 1 X 3
B = [3 1];            % to compare the size of vector entered by user is 3 X 1
f = 0;                %setting flag to use in loop

% loop until our requirement(untill 3 try or when entring correct input)
i=0;
while(i<n)
    while f<3 
        V = input('Enter a 1 X 3 vector: ');                        %getting user input and adding it two V
        s = size(V);                                                %determining size of entered vector 
    
        if (isequal(s,A)==1)                                        % checking that size of V is 1 X 3
            fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
            disp(V);                                                % displaying V
            Value=[Value;V];                                        % Appending V to the set of other inputs
            break;                                                  % setting termination condition for loop
       
        elseif (isequal(s,B)==1)                                    % checking that size of V is 3 X 1
            fprintf('Error: You entered a 3 X 1 vector! \n');       % errror message displaying
            V = V.';                                                % transposing vector to 1 X 3
            fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
            disp(V);                                                % displaying V
            Value=[Value;V];                                        % Appending V to the set of other inputs
            break;                                                  % setting termination condition for loop
                                                          
        else
            fprintf('Entrored dimesion is wrong!\n');               % printing error when user entry size is wrong
            f = f + 1;                                              %incrementing chance count
        end
    end
    if(f==3)
        fprintf('Your Chances are over!\n'); 
        break;                                                      % printing the error message if trIES is over 
    end
    i=i+1;
end

Second Approach:

Value=[];

%Get a 1 X 3 vector and print the same
A = [1 3];            % to compare the size of vector entered by user is 1 X 3
B = [3 1];            % to compare the size of vector entered by user is 3 X 1
f = 0;                %setting flag to use in loop

% loop until our requirement(untill 3 try or when entring correct input)
i=true;
while(i==true)
    while f<3 
        V = input('Enter a 1 X 3 vector: ');                        %getting user input and adding it two V
        s = size(V);                                                %determining size of entered vector 
    
        if (isequal(s,A)==1)                                        % checking that size of V is 1 X 3
            fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
            disp(V);                                                % displaying V
            Value=[Value;V];                                        % Appending V to the set of other inputs
            break;                                                  % setting termination condition for loop
       
        elseif (isequal(s,B)==1)                                    % checking that size of V is 3 X 1
            fprintf('Error: You entered a 3 X 1 vector! \n');       % errror message displaying
            V = V.';                                                % transposing vector to 1 X 3
            fprintf('The resulting 1 X 3 vector is: \n');           % assigning message to display
            disp(V);                                                % displaying V
            Value=[Value;V];                                        % Appending V to the set of other inputs
            break;                                                  % setting termination condition for loop
                                                          
        else
            fprintf('Entrored dimesion is wrong!\n');               % printing error when user entry size is wrong
            f = f + 1;                                              %incrementing chance count
        end
    end
    if(f==3)
        fprintf('Your Chances are over!\n'); 
        break;                                                      % printing the error message if trIES is over 
    end
%     check=input('Enter 0 if you want to input more values, else enter any other number:');   
    if check ~= 0
        i=false;
    end
end

For both of the approaches all the values are stored in "Value" and can be accessed as :

Value(x,:)

Here it will return the input that was given at x iteration