please give me the explanation
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clc;clear all;close all;
r=imread('fig2_background.jpg'); % read the image
[rows columns numberOfColorChannels] = size(r);
if numberOfColorChannels > 1
r = rgb2gray(r); % converting image to grayscale
else
r = r; % It's already gray.
end
[row, col]=size(r);
g=zeros(row,col);//
I=zeros(size(r));
I=r;
S=zeros(size(r));
S(80:82,172:174)=ones(3,3); %initial seed image
figure,imshow(S),title('Initial Seed Image')
----------------------------------------------------------------
T=50; %threshold value
r=double(r);
w = [1 1 1;1 1 1;1 1 1 ];
SI=size(r);
p=size(r);
for x=2:1:p(1)-1
for y=2:1:p(2)-1
a1=[w(1)*S(x-1,y-1) w(2)*S(x-1,y) w(3)*S(x-1,y+1) w(4)*S(x,y-1) w(5)*S(x,y) w(6)*S(x,y+1) w(7)*S(x+1,y-1) w(8)*S(x+1,y) w(9)*S(x+1,y+1)];
AI(x,y)=min(a1);
end
end
SI= padarray(AI,[1 1],'symmetric','post');
SI=uint8(SI);
J=find(SI);
S1=r(J); % seed value obtained from SI
seedvalue=S1;
S=abs(r- seedvalue)<= T; % thresholding the absolute difference between original image & seed value
figure,imshow(S),title('thresholding output')
for p=1:1:row
for q=1:1:col
if(SI(p,q)==1)
for n=q:1:col
if S(p,q)==S(p,n)
g(p,n)=1;
end
end
for n=q:(-1):1
if S(p,q)==S(p,n)
g(p,n)=1;
end
end
for n=p:-1:1
if S(p,q)==S(n,q)
g(n,q)=1;
end
end
for n=p:1:row
if S(p,q)==S(n,q)
g(n,q)=1;
end
end
for n1=p:1:row
for n2=q:1:col
if S(p,q)==S(n1,n2)
g(n1,n2)=1;
end
end
end
for n1=p:1:row
for n2=q:(-1):1
if S(p,q)==S(n1,n2)
g(n1,n2)=1;
end
end
end
for n1=p:-1:1
for n2=q:(-1):1
if S(p,q)==S(n1,n2)
g(n1,n2)=1;
end
end
end
for n1=p:-1:1
for n2=q:1:col
if S(p,q)==S(n1,n2)
g(n1,n2)=1;
end
end
end
end
end
end
g=uint8(g);
SE = ones(1,1);
g =bwlabel(imdilate(g,SE),8);%reconstructing the image
%g=logical(g)
%I(g)=0
%figure,imshow(I),title('Final Output')
Lrgb = label2rgb(g);
figure, imshow(Lrgb)
title('output of region growing process')
figure, imshow(I), hold on
himage = imshow(Lrgb);
set(himage, 'AlphaData', 0.3);
title('final output superimposed on original image')
3 Comments
mohammed
on 20 Feb 2014
what do you want?
yuvashree
on 21 Feb 2014
Image Analyst
on 21 Feb 2014
Looks like it does region growing to me, at least that's what the title says.
Answers (1)
Walter Roberson
on 21 Feb 2014
0 votes
No, we cannot explain the code. Ask the person who wrote it.
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