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新手:题目是“生成相量 A,其元素为区间[1,999]内的整数,然后找出 A 中能被 13 整除且 大于 500 的数。”
A=[1:999]; j=1; i=A for i=A if A(i)>500; if rem(A(i),13)==0; C(j)=A(i); j=j+1; end ...
3 years ago | 1 answer | 0