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Answered
regarding phase compensation?
Hello, sir, in the code above: S3 = S2.*exp(-i*theta_estimate/(length(S2))); Why we have to divide it by lengt...
regarding phase compensation?
Hello, sir, in the code above: S3 = S2.*exp(-i*theta_estimate/(length(S2))); Why we have to divide it by lengt...
3 years ago | 0
