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k^n matrix
on 11 Oct 2022
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n=13;k=3;
x=k^n;
z=[];
for i=1:n
y=[];
for j=1:k
y=[y;j*ones(k^(i-1),1)];
end
z=[z repmat(y,x/length(y),1)];
end
imagesc(z)
colorbar
title('Search For My old Projects and vote the best :) ')
xlabel('Ahmed Raafat')