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on 4 Oct 2021
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for l=1:9
h=1/2;t=1/3;b=2/3;a=h/sqrt(3);for k=exp(6:1/l:9)
e=sin(pi/3)/4;x=-[h,e,h-1,e,0,e-sqrt(3/4),h,e,h,e]*k;for j=1:6
y=[];
for i=1:2:numel(x)-3
y=[y,x(i:i+3)*[1,0,b,0,h,a,t,0;0,1,0,b,-a,h,0,t;0,0,t,0,h,-a,b,0;0,0,0,t,a,h,0,b]];end
x=y;end;line(x(1:2:end),x(2:2:end));end;end

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