given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Which doors are open?
Project Euler: Problem 10, Sum of Primes
Remove the two elements next to NaN value
How many monitors are connected ?
03 - Matrix Variables 5
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