Hello All!
Well I found this one fun to figure out, all you have to do is make a matrix of 1's or 0's (true or false) that show whether or not a number in a matrix is sitting directly next to (a neighbor) that is number that is +1 or -1 or == to that of the original number. Here are some examples:
M1 = [1 2 1;
5 6 7;
2 3 6]
SO now find numbers next to one another that are +1 of each-other.
output = [1 1 1;
1 1 1;
1 1 1]
One more:
M2 = [8 8 8;
4 4 4;
1 9 7]
SO now find numbers next to one another that are +1 of each-other.
output = [1 1 1;
1 1 1;
0 0 0]
One more:
M3 = [1 8 5;
4 10 22;
1 66 7]
SO now find numbers next to one another that are +1 of each-other.
output = [0 0 0;
0 0 0;
0 0 0]
Well good luck!
Solution Stats
Problem Comments
Solution Comments
Show commentsProblem Recent Solvers86
Suggested Problems
-
Swap the first and last columns
22688 Solvers
-
Numbers with prime factors 2, 3 and 5.
683 Solvers
-
Back to basics 22 - Rotate a matrix
937 Solvers
-
356 Solvers
-
Find the index of n in magic(n)
273 Solvers
More from this Author17
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Good problem. You should generalise it with more tests (size of the matrix, different gap...).
I suspect that my solution isn't correct.