If a chessboard were to have wheat placed upon each square such that one grain were placed on the first square and each successive square after had double the amount of grains as the square before. How many grains of wheat would be on the chessboard at the finish?
Assume the chess board is n by n squares.
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Shouldn't the solution for n=-1 be NaN, rather than 'NaN' which is a character array?
I agree with Ken , we expect NaN and not the string 'NaN'
I believe you should also change the assert for the case n=-1 to be isequalwithnan, since isequal(NaN,NaN) is false.
yeap you have just rescored the problem but you need to use isequalwithnan,
actually you need to use isequalwithequalnans
tests 5 and 6 does not work properly. those numbers are out of precision, and for test 6 it couldn't be fixed even with uint64 used instead of type double
This problem is simply wrong. The right answer is
sum(1:2^(n^2-1))
if we where to sum ALL the grains on the board....