Problem 231. Differential equations I

Created by Tomasz

Difficulty:Rate

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Given a function handle f an initial condition y0 and a final time tf, solve numerically the differential equation

dy/dt = f(y)

for the function y(t) between t=0 and t=tf. Give as a result res=y(tf).

Example:

   f = @(x) -x;
   tf= 1;
   y0= 1;

 => y(tf) = 1/e = 0.367879441171442

Remarks: aim at a relative precision of around 1e-6. The function is analytic in the interval [0,1].

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Last Solution submitted on Mar 18, 2025

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warnerchang on 7 Aug 2023

As Nikolaos mentioned, the last test needs a fix. The value of 'a' is not transferred into the function handle 'f', and 'a' is just a char (not a value) in 'f'.

Christian Schröder on 7 Aug 2023

The last test case is not broken. When you define an anonymous function that includes variables, those variables are stored along with the function and remain available to it. This is true also when handles to the anonymous function are passed around, or when the variables in question are cleared from memory. See https://www.mathworks.com/help/matlab/matlab_prog/anonymous-functions.html#f4-71621 .

Kartik on 24 Dec 2024

I am completely lost while solving it, please someone guide me

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