# i want to assign number of tasks to fog nodes randomly son in the matrix i will have different solution and i got the same solution repeated

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maria alseid on 14 Aug 2021
Commented: maria alseid on 20 Aug 2021
lb=250;
ub= 1000;
dim = 5;
pop=5;
%Initialization
fognodesnumber = 3;
for i = 1 : pop %pop=N, population size
for task = 1 : dim
indices2 = randperm(fognodesnumber);
for FN=1:fognodesnumber
% Evaluate the fitness of the new solution
end
end
end
so the reult i got for x is
x =
357.1360 357.1360 357.1360
520.0463 520.0463 520.0463
370.7144 370.7144 370.7144
370.7144 370.7144 370.7144
663.3892 663.3892 663.3892
but i need each column the numbers to be distributed differently

Shravan Kumar Vankaramoni on 17 Aug 2021
Hi,
for FN=1:fognodesnumber
end
In the above loop, task( row number ) is a constant value. Basically you are storing same value in the entire row. To get different values in the columns of the same row, you can try the below code. It is randomizing the value to be stored.
for FN=1:fognodesnumber
end
maria alseid on 20 Aug 2021