Sorting out raw index from raw data

Hi Everyone

I have some cyclic data which is similar to the attached.

The data is from creep fatigue data, you can regard 1 as fatigue and 0 as creep,

what I want to achieve is as follows

with only raw data given

first define the range of each cycle

then for each cycle I would like to sort out the row index or range of both fatigeu and Creep Portion

I am achieve an example through excel by eyeball but could not find a way with matlab as there is lot of data to sort.

Can anyone help me with this problem?

Thank you very much

Answer 1

[Dave B]

A trick to these kinds of problems is to combine find and diff, diff is good at marking the transitions between states and find is good at turning those into row numbers.

One thing to watch out for - you'll probably need to check the initial and final state, this code assumes that the initial state is a 1 and the final state is a 0, but the more general case would check these and adapt...I'll leave that part up to you.

% copy of your data
x=[1 1 1 0 0 1 1 1 0 0 0 0 1 1 1 0 0];

% note that really you only need to call find twice, the repeats are just to make it look similar
oneA=find(diff([0 x])==1);
oneB=find(diff([0 x])==-1)-1;
oneC=find(diff([0 x])==-1);
oneD=find(diff([x 1])==1);

disp([oneA;oneB;oneC;oneD])

     1     6    13
     3     8    15
     4     9    16
     5    12    17

[ZHE LYU]

Thank you so much!