could anyone help me how to solve the error in the following code

I am having cell array
B=10x1 cell
which contains
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
I used the following code to convert it
A=cell(size(B));
for i=1:numel(B)
A{i}=splitapply(@(x){x}, 1:numel(B{i}) ,B{i});
disp("YTest{" +i+ "}:"), B{i}
for j=1:numel(A{i})
disp("A{" +i+ "}{"+j+"}:"), A{i}{j}
end
disp ' '
end
But it results in error. Could anyone please help me to overcome it.

2 Comments

what is the error, exactly?
what is the line
splitapply( @(x) {x}, 1:numel(B{i}) ,B{i} )
supposed to do? it looks like that's where is problem to me
Error using splitapply
Group numbers must be a vector of positive integers, and cannot be a sparse vector.
Error in line 3
A{i}=splitapply(@(x){x}, 1:numel(B{i}) ,B{i});

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Answers (1)

The last parameter to splitapply must be a vector of positive integers, one for each row of input, with the number indicating which group the row belongs to.
It is not clear that your B values are integers. It is clear that B{i} is not a vector.
Perhaps you accidentally exchanged the second and third parameters.

8 Comments

The code executes
A=cell(size(B));
for i=1:numel(B)
A{i}=splitapply(@(x){x}, 1:numel(B{i}) ,B{i});
disp("YTest{" +i+ "}:"), B{i}
for j=1:numel(A{i})
disp("A{" +i+ "}{"+j+"}:"), A{i}{j}
end
disp ' '
end
when B is
1x4 double
Now I want to modify the code as now B is
10x4 double
Could you please help me how to execute the code for
B=10x4 double.
That is not possible. The last parameter to splitapply must be a vector. Never a 2d array.
Ok. Is there any other way that can convert 10X 4 double into 10X4 cell.
if i use num2cell it executes, but the result is different from what i need.
I think i need to use splitapply but I am not aware how to use it in my case.
Could you please help me on this.
Unfortunately, you did not explain what output you want.
rng(12345)
B{1} = randi(9, 3, 4);
B{2} = randi(9, 3, 4);
celldisp(B)
B{1} = 9 2 9 6 3 6 6 7 2 6 7 9 B{2} = 1 6 9 7 1 8 7 5 3 8 6 3
What exact output would you want for the above?
I want B to convert to A.
B=3x1 cell
2x3 double - [1,1,1 - 1st row
1,2,2]- 2nd row
A=3x1 cell
2x1cell - [1,2,3] 1st row
2x2cell - [1] [2,3] 2nd row

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Asked:

on 16 Jul 2021

Commented:

on 17 Jul 2021

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