How to get quotient value after division without round off?

I want to get quotient (only integer value) after division of two numbers without rounding off.

        n1 = I1(i,j) +1;
        for k1= 0:7
            l1(8-k1) = rem(n1,2);
            n1 = fix(n1/2);   
        end
        
        when n1 = 157  in first line  :
        then in fourth line after dividing by 2 , n1 is taking 79 (157/2 = 78.5) value
        but i want n1 to take 78 value.
        

[Khushboo Singla]

There is one more doubt as::

In Command Window

when i write fix(157/2) gives answer as 78

but when i write fix(n1/2) gives answer as 79

and according to my code i want to write fix(n1/2) and wwant to get answer as 78 i.e quotient without round off !!

[dpb]

>> n1=157;
>> fix(n1/2)
ans =
    78
>> 

You've done something else you've not told us about first...like an intermediate store with a rounding operation, maybe.

Even in your code;

>> n1=157;for k1= 0:7
            l1(8-k1) = rem(n1,2);
            n1 = fix(n1/2)
        end
n1 =
    78
n1 =
    39
n1 =
    19
n1 =
     9
n1 =
     4
n1 =
     2
n1 =
     1
n1 =
     0
>> 

Answer 1

[Mouhamed Niasse]

Hello,

I tried to execute your portion of code but, just as expected, n1 has the value 78 not 79 for me.

Try using the function 'floor' instead of 'fix', they normally give the same output for positive input values.

[Khushboo Singla]

Thankyou so much. Though same problem persisted in my code BUT i got another solution

as I subtracted remainder(from third line) from the number(n1) everytime so that it will give only interger value after division as shown:

n = 157;
for k1= 0:7
            l1(8-k1) = rem(n1,2);
            n1 = fix((n1-l1(8-k1))/2)
        end

Answer 2

[Steven Lord]

If one or both of the numbers are stored as an integer type you could use the idivide function.

idivide(int16(157),2)

ans = int16 78