Creating a new matrix in a loop from a pre-determined matrix

Hello,

I want to create a new matrix "a" from a pre-determined matrix "x". I can do it like this if a and x have 3 rows:

ax = ((max(x(1,:))-min(x(1,:)))/10);
ay = ((max(x(2,:))-min(x(2,:)))/10);
az = ((max(x(3,:))-min(x(3,:)))/10);

But I want to make this with a for loop in a more general and compact way.

for j=1:1:numel(x)
a(j) = ((max(x(j,:))-min(x(j,:)))/10);
end

If I try to do it like this I get dimensional mismatch errors. It seems notoriously hard for me to create matrices in for loops with pre-determined set of conditions in MATLAB.

Answer 1

[Azzi Abdelmalek]

a=[1 5 3;4 10 6;7 11 19;20 30 50]
c=(max(a')-min(a'))/10
ax=c(1)
ay=c(2)
az=c(3)

[white chocolate farm]

Thanks but I need to make this with a for loop because number of rows of x can change, thus I need to make it more general. For example it could be 5 instead of 3. If I could make a for loop, I would just write 1:numel(x) which could generate what I want.

[Azzi Abdelmalek]

This is general

a=[1 5 3;4 10 6;7 11 19;20 30 50]
c=(max(a')-min(a'))/10

% c contains all your values

Answer 2

[Roger Stafford]

Your for-loop isn't right. The 'numel' will give you too many indices. It should be

 n = size(x,1);
 a = zeros(n,1);
 for j = 1:n
  etc.

[white chocolate farm]

Yes, thanks but it still won't work because of what's inside the for loop I guess. I need to change a(j) part I assume.