Creating a new column in a table which is true or false

Hi,

I have to tables. One is called subsetx the other one is called subsety. In subsetx are two columns one is called ID and the other one SIC. It looks like this:

ID SIC

10000 3990

10000 3990

.

.

.

10001 4920

.

.

.

10002 6020

In subsety i have two rows with value 3990 4920.

I would like to create a new column in subsetx of logical type (true or false)

If variable SIC matches one of the numbers in subsety I would like to get a 1 if not i would like to get a 0.

The proble is you cant compare table with diffrent numbers of row.

I did attached the two subsets.

How can I solve this problem ?

Thank you in advance

Answer 1

[Steven Lord]

rng default
id = (1:10).';
SIC = randi(3, 10, 1);
t = table(id, SIC)

t = 10×2 table
    id    SIC
    __    ___

     1     3 
     2     3 
     3     1 
     4     3 
     5     2 
     6     1 
     7     1 
     8     2 
     9     3 
    10     3 

t.is1or2 = ismember(t.SIC, [1 2])

t = 10×3 table
    id    SIC    is1or2
    __    ___    ______

     1     3     false 
     2     3     false 
     3     1     true  
     4     3     false 
     5     2     true  
     6     1     true  
     7     1     true  
     8     2     true  
     9     3     false 
    10     3     false 

[Luca]

Thank you very much it worked.

Answer 2

[David Fletcher]

vals=subsety{:,1};
subsetx{:,3}=subsetx.SIC==vals(2,1)|subsetx.SIC==vals(1,1);

[Luca]

Thank you it worked