Trying to Display a found answer with units

Here I have a script I am trying to write a script but I need my answers (within the if-statement) to output"Water Volume = amount found m^3(unit needed to display"

so i.e Water Volume = 4.0235 m^3

This is what I have so far and I have another script to "call" this function where it lists:

tankvolume( -5)

tankvolume(15)

tankvolume(50)

tankvolume(60)

function Vtotal = tankvolume(h)

rc = 10;

rf = 20;

hc = 30;

hf = 25;

if h < 0

Vtotal = -1;

disp('Error h Cannot be Negative')

elseif h < hc && h > 0

Vtotal = pi*rc*rc*h;

fprintf ('Water Total = % m^3, Vtotal') % Volume of Water in Tank in m^3

elseif hc < h && h < hc + hf

rh = rc+((h-hc)*(rf-rc))/hf;

Vtotal = pi*rc*rc*hc+(pi*(h-hc)*(rc*rc+rc*rh+rh*rh))/3; % Volume of Water in Tank in m^3

fprintf ('Water Total = % m^3, Vtotal')

else

Vtotal = -1;

disp('Error Overflow')

end

end

any advice?

[Miriah Dudley]

UPDATE: ('Water Total = %6.2f m^3\n', Vtotal)

Found a way to print Water total =

HOWEVER, I still get ans = as an output and I don't want that. Anyway to avoid it from being an output?

Answer 1

[David Fletcher]

function Vtotal = tankvolume(h) 
rc = 10;
rf = 20;
hc = 30;
hf = 25;
if h < 0
Vtotal = -1;
disp('Error h Cannot be Negative')
elseif h < hc && h > 0
Vtotal = pi*rc*rc*h;
fprintf ('Water Total = %f m^3\n', Vtotal) % Volume of Water in Tank in m^3
elseif hc < h && h < hc + hf
rh = rc+((h-hc)*(rf-rc))/hf;
Vtotal = pi*rc*rc*hc+(pi*(h-hc)*(rc*rc+rc*rh+rh*rh))/3; % Volume of Water in Tank in m^3
fprintf ('Water Total = %f m^3\n', Vtotal)
else
Vtotal = -1;
disp('Error Overflow')
end
end

[David Fletcher]

If desired, you can add a modifer to the %f to limit the precision (such as %6.2f)