How to format a cell array to different rows

With this following code:

raw = fileread('testdata.txt');

data = regexp(raw,'[+-]?\d+\.?\d*', 'match');

g=(cellfun(@str2num,data))

It results in g to look like: [1003 ...... 1009...1016....1020] , where its a 1x242 array.

I want to split into multiple rows to have the data look like this instead:

[1003, ,........;

1009 , .......;

1016..........;

1020.........; ]

Could anyone provide some help in how to accomplish this?

Answer 1

[Star Strider]

Try this:

fidi = fopen('testdata.txt', 'rt');
C = textscan(fidi, '%f', 'Delimiter',' ', 'MultipleDelimsAsOne',1); % Cell Array Output
fclose(fidi);
V = [C{:}];                                                         % Extract Numerical Vector
segments = [find(log10(V) >= 3); numel(V)+1];                       % Determine Segment Limits
seglen = diff(segments);                                            % Segment Lengths (For ‘mat2cell’)
Out = mat2cell(V, seglen, 1);                                       % Cell Array Of Segments

Row1 = Out{1}(1:7).'                                                % Display First 7 Elements
Row2 = Out{2}(1:7).'                                                % Display First 7 Elements
Row3 = Out{3}(1:7).'                                                % Display First 7 Elements
Row4 = Out{4}(1:7).'                                                % Display First 7 Elements

I have no idea how robust it would be to other such files. It works with this one.