division of a single column matrix
Show older comments
i have a single column matrix A=0 0 0 1 1 1 1 0 0 0 0 2 2 2 2 0 0 0 0 1 1 1 now i have to divide this in to several matrices such whenever 0 changes to 1 or 2 i want a new matrix in this case A1= 1 1 1 1 0 0 0 0; A2=2 2 2 2 0 0 0 0 ;A3= 1 1 1 which are also single column matrices ............using for loop
1 Comment
Oleg Komarov
on 16 May 2011
See my double edited answer in the previous post.
Answers (1)
Andrei Bobrov
on 16 May 2011
in this case
A = A(:);
I = cumsum([0;diff(A)]~=0 & (A == 1 | A == 2));
out = arrayfun(@(x)A(I==x),1:max(I),'un',0);
Dear bilhan! I think it is necessary to remove the question. See commentary by Oleg Komarov
4 Comments
Oleg Komarov
on 16 May 2011
This a duplicate post and the op asked a loop solution: http://www.mathworks.com/matlabcentral/answers/7497-dividing-a-column-matrix-based-on-the-no
Andrei Bobrov
on 16 May 2011
Hi Oleg, i'm to blame, did not notice.
Oleg Komarov
on 16 May 2011
You can add your answer to the other post. Multiple interpretations are always useful.
Andrei Bobrov
on 16 May 2011
well
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!