# How to Compare a Table within some Tolerance Values?

4 views (last 30 days)
ercan duzgun on 15 Feb 2021
Commented: ercan duzgun on 15 Feb 2021
Dear Matlab community, I would like to ask how can I compare some values in a table within some percentage fault tolerance?
For example assume that I have values of (column matrix). I am searching these x column matrix values in a table.
The table matrix is table=table=table=[ 25.10, 200.75, 25.05, 50, 25.05; 30.00, 50.75, 29.95, 80, 30.05; 50.20, 50.75, 40.30, 50, 40.30];
Therefore, the third column of the Table is acceptable for me. And I want to find its column number, locations in the table matrix.
My MATLAB codes would be:
x=[25.10;
30.00;
40.35];
table=[ 25.10, 200.75, 25.05, 50, 25.05;
30.00, 50.75, 29.95, 80, 30.05;
50.20, 50.75, 40.30, 50, 40.30];
I would like to find that the location of the third and fifth column: location=3;5 . I can find it using if command for each element of the matrix, but I wanted to ask if there is easier way.
The first column is not accpetable for me, because the last element is not equivalent with tolerance with the last element of x.
How can I find this? Thanks in advance.
PS: I found this similar question here: https://www.mathworks.com/matlabcentral/answers/302059-how-to-find-the-closest-values-with-tolerance-in-a-matrix-given-a-specific-value , but my question is different, because if I it, I also find first two elements of the first column. But I don't want it. All three elements of the matrix should be in the tolerance limit.
My code for it:
x=[25.10;
30.00;
40.35];
table=[ 25.10, 200.75, 25.05, 50, 25.05;
30.00, 50.75, 29.95, 80, 30.05;
50.20, 50.75, 40.30, 50, 40.30];
tolerance_table=table*(1/100)
abs(x-table)<tolerance_table
>> ans=
3×5 logical array
1 0 1 0 1
1 0 1 0 1
0 0 1 0 1
[ii,jj]=find(abs(x-table)<tolerance_table)
ii =
1
2
1
2
3
1
2
3
jj =
1
1
3
3
3
5
5
5
I don't want the first column included in the solutions. I want to find 3 and 5 only. Not 1.

Alan Stevens on 15 Feb 2021
Here's one possibility
x=[25.10;
30.00;
40.35];
table=[ 25.10, 200.75, 25.05, 50, 25.05;
30.00, 50.75, 29.95, 80, 30.05;
50.20, 50.75, 40.30, 50, 40.30];
tolerance_table=table*(1/100);
d = abs(x-table)<tolerance_table;
c = find(sum(d)==3);
ercan duzgun on 15 Feb 2021
@Alan Stevens thank you very much.

Walter Roberson on 15 Feb 2021
cols = find(all(abs(x-table)<tolerance_table,1))
ercan duzgun on 15 Feb 2021
@Walter Roberson thank you very much.

R2019b

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