Delete Cells from Cell Array, when size is less than 50% of biggest cell

Hey guys, I have an Cell Array, with cells only containing nx2 matrices.

>> a = {[1,2;3,4;5,6;7,8],[9,10;11,12],[13,14;15,16;17,18]}
>> celldisp(a)
 
a{1} =
     1     2
     3     4
     5     6
     7     8
a{2} =
     9    10
    11    12
a{3} =
    13    14
    15    16
    17    18

I am tying to find a way to only keep thoose Cells from the Cell Array which size (number of rows) is greater than 50% of the biggest Cell, so that my output looks like this:

>> a = {[1,2;3,4;5,6;7,8],[13,14;15,16;17,18]}
a{1} =
     1     2
     3     4
     5     6
     7     8
a{2} =
    13    14
    15    16
    17    18

Answer 1

[KALYAN ACHARJYA]

Here one way:

The given cell data

a={[1,2;3,4;5,6;7,8],[9,10;11,12],[13,14;15,16;17,18]}

Check data

a =
  1×3 cell array
  {4×2 double}    {2×2 double}    {3×2 double}

Get the rows ('1') of all cell elements, if columns, use '2'

cell_sizes=cellfun('size',a,1);

Get the max size of rows and 50% of the row size

max_size=max(cell_sizes);
th=max_size*0.5;

Apply the condtion for rows more than 50% of max size (Get the indices, those are lesser or equal)

idx=find(cell_sizes<=th);

Assign all cell elements with particular indices idx with blanks ([])

a(idx)=[];

Remove all those are blanks cell elements

a(cellfun('isempty',a)) = []

Result:

a =
  1×2 cell array
  {4×2 double}    {3×2 double}

[Stephen23]

Simpler to skip the loop and skip the second cellfun and just use the index directly:

a(idx) = []

The find is not required.

[Ko Fa]

Thanks for your help Kalyan and Stephen

[KALYAN ACHARJYA]

@Stephen CobeldickYes sir, I did, so. Initailly I missed it. Thanks always