Can anyone say
why it is showing inf as output as shown in the screenshot attached, when I ask radius and centre of curvature for sqrt(X)+sqrt(y)==sqrt(a),when x = 3???
Why it is not showing a numerical value???
Kindly solve this problem.

2 Comments

Maybe you forgot to attach the screenshot?
Sorry sir I thought I had attached the screenshot. Now I had attached it.

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 Accepted Answer

Hi Nagaraj,
You will have to first change your equation to the form of y = f(x) and then use the formulae to find the radius and center of curvature. The code is given below for your reference:
syms y(x) a
y(x) = (sqrt(a)-sqrt(x))^2; % Re-arranged the equation
x1 = 3;
c1 = x - (diff(y,x)*(1+(diff(y,x))^2))/diff(y,x,2);
c1 = c1(x1) % Found x-coordinate of center of curvature
y1 = y(x1);
c2 = y + (1+(diff(y,x))^2)/diff(y,x,2);
c2 = c2(y1) % Found y-coordinate of center of curvature
Center = [c1,c2];
Point = [x1,y1];
Radius = ((x1-c1)^2 + (y1-c2)^2) % Distance between the point and the center gives radius of curvature
For additional information on the 'diff' function, refer to the following link:
Regards,
Divija

3 Comments

Thank you so much madam for solving my problem.
If you have any more questions, then attach your data and code to read it in with the paperclip icon, in a new question, after you read this:
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@Divya I think you ignored my last comment totally. Let me give instructions step by step.
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  3. In the edit box, click the paperclip icon and attach your .m file, and any data files that need to be read in.
  4. Click the "Post Question" button to submit your question. Then it will appear on the list.

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