Symbolic matrix with symbolic size

I am trying to define a symbolic matrix with symbolic indices

Normally, I know that a symbolic matrix A which has 2 rows and 4 columns is defined as :

A = sym('A', [2 4])

But I want to define it with m rows and n columns, when I use the following code, I have an error message: Error using sym (line 253) Second argument must be assumption or size vector:

syms m n

assume(m,'integer')

assumeAlso(m>=0)

assumeAlso(m<=M-1)

assume(n,'integer')

assumeAlso(n>=1)

assumeAlso(n<=2^(k-1))

A = sym('A', [m n])

So, how can I accomplish this?

Thank you in advance.

Answer 1

[Raunak Gupta]

Hi,

As mentioned in this question , Matrices with unknown size is not supported in MATLAB and thus the correct error message is displayed. You can try the workaround given in the answer by defining a large matrix and then cropping it based on the actual values of ‘m’ and ‘n’.